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  1. #include <iostream>
  2. #include <bits/stdc++.h>
  3. using namespace std;
  4.  
  5. bool isAnagram(string s, string t) {
  6.     if (s.size() != t.size()) {
  7.         return false;
  8.     }
  9.  
  10.     int arr1[26] = {0};
  11.     int arr2[26] = {0};
  12.     int n = s.size();
  13.  
  14.     for (int i = 0; i < n; i++) {
  15.         int a = s[i] - 'a';
  16.         int b = t[i] - 'a';
  17.  
  18.         arr1[a]++;
  19.         arr2[b]++;
  20.     }
  21.  
  22.     for (int i = 0; i < 26; i++) {
  23.         if (arr1[i] != arr2[i]) {
  24.             return false;
  25.         }
  26.     }
  27.  
  28.     return true;
  29. }
  30.  
  31. int main() {
  32.     string s, t;
  33.     cin >> s >> t;
  34.  
  35.     if (isAnagram(s, t)) {
  36.         cout << "true";
  37.     } else {
  38.         cout << "false";
  39.     }
  40.  
  41.     return 0;
  42. }
Success #stdin #stdout 0s 5320KB
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stdin
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anagram nagaram
stdout
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true
https://ideone.com/3xX8Ow
language:
C++14 (gcc 8.3)
created:
6 hours ago
visibility:
public

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