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  1. #include <stdio.h>
  2. #include <stdint.h>  // For uintptr_t
  3.  
  4. int main() {
  5.     int x = 42;
  6.     int *p = &x;
  7.  
  8.     uintptr_t addr = (uintptr_t)p;  // Convert pointer to integer
  9.     printf("Address as integer: %lu (hex: 0x%lx)\n", addr, addr);
  10.  
  11.     return 0;
  12. }
Success #stdin #stdout 0.01s 5288KB
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stdin
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Standard input is empty
stdout
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Address as integer: 140732968307812 (hex: 0x7ffef2958c64)
https://ideone.com/7NK8HH
language:
C++ (gcc 8.3)
created:
7 days ago
visibility:
public

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