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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4.     int i;
  5.     int data[10];
  6.     int j=0;
  7.  
  8.     scanf("%d", &i);
  9.     printf("10進数で%dは、",i);
  10.  
  11.  
  12.     while(i>0){
  13.         data[j]=i%2;
  14.         i=i/2;
  15.         j++;
  16.     }
  17.  
  18.     printf("2進数で表すと");
  19.     for (int i =j-1; i>=0; i--){
  20.         printf("%d", data[i]);
  21.     }
  22.     printf("となる\n");
  23.  
  24.     return 0;
  25. }
Success #stdin #stdout 0.01s 5288KB
comments (?)
stdin 
31
stdout 
10進数で31は、2進数で表すと11111となる
https://ideone.com/86o0dH
language:
C (gcc 8.3)
created:
13 days ago
visibility:
public

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