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  1. #include <stdio.h>
  2. int main() {
  3.     int i, j, k, n;
  4.     for (n = 100; n < 1000; n++) {
  5.         i = n / 100;
  6.         j = (n % 100) / 10;
  7.         k = n % 10;
  8.         if (i * i * i + j * j * j + k * k * k == n) {
  9.             printf("%d\n", n);
  10.         }
  11.     }
  12.     return 0;
  13. }
  14.  
Success #stdin #stdout 0s 5284KB
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https://ideone.com/I2Ze2f
language:
C (gcc 8.3)
created:
5 days ago
visibility:
public

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