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  1. #include <stdio.h>
  2.  
  3. void calculate(int (*a)[4]) {
  4.     int sum[3] = {0};
  5.  
  6.     for (int i = 0; i < 3; i++) {        // 3 行
  7.         for (int j = 0; j < 4; j++) {    // 各行 4 列
  8.             sum[i] += a[i][j];
  9.         }
  10.     }
  11.  
  12.     // 結果表示
  13.     for (int i = 0; i < 3; i++) {
  14.         printf("sum[%d] = %d\n", i, sum[i]);
  15.     }
  16. }
  17.  
  18. int main() {
  19.     int a[3][4] = {1,2,3,4 , 5,6,7,8 , 9,10,11,12};
  20.  
  21.     calculate(a);
  22.  
  23.     return 0;
  24. }
  25.  
Success #stdin #stdout 0.01s 5292KB
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stdin
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Standard input is empty
stdout
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sum[0] = 10
sum[1] = 26
sum[2] = 42
https://ideone.com/lmpOMY
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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