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  1. #include<stdio.h>
  2. int main()
  3. {
  4. 	int n;
  5. 	printf("Enter number of processes: ");
  6. 	scanf("%d",&n);
  7. 	int at[n],bt[n],ct[n],tat[n],wt[n],rt[n];
  8. 	for(int i=0;i<n;i++)
  9. 	{
  10. 		printf("Enter the arrival and burst time for  p%d : ",i+1);
  11. 		scanf("%d %d",&at[i],&bt[i]);
  12.  
  13. 	}
  14.  
  15. 	for(int i=0;i<n-1;i++)
  16. 	{
  17. 		for(int j=i+1;j<n;j++)
  18. 		{
  19. 			if(at[i]>at[j])
  20. 			{
  21. 				int temp;
  22. 				temp=at[i];at[i]=at[j];at[j]=temp;
  23. 				temp=bt[i];bt[i]=bt[j];bt[j]=temp;
  24. 			}
  25. 		}
  26. 	}
  27.  
  28. 	//ct
  29.  
  30. 	ct[0]=at[0]+bt[0];
  31. 	for(int i=1;i<n;i++)
  32. 	{
  33. 		if(ct[i-1]<at[i])
  34. 		ct[i]=at[i]+bt[i];
  35. 		else
  36. 		ct[i]=at[i-1]+bt[i];
  37. 	}
  38.  
  39.  
  40. 	//tat wt rt
  41.  
  42. 	for(int i=0;i<n;i++)
  43. 	{
  44. 		tat[i]=ct[i]-at[i];
  45. 		wt[i]=tat[i]-bt[i];
  46. 		rt[i]=wt[i];
  47. 	}
  48.  
  49. 	printf("\nP\tAT\tBT\tCT\tTAT\tWT\tRT\n");
  50. 	for(int i=0;i<n;i++)
  51. 	printf("P%d\t%d\t%d\t%d\t%d\t%d\t%d\n",i+1,at[i],bt[i],ct[i],tat[i],wt[i],rt[i]);
  52. }
Success #stdin #stdout 0s 5288KB
comments (?)
stdin 
 4
0 2
1 2
5 3
6 4
stdout 
Enter number of processes: Enter the arrival and burst time for  p1 : Enter the arrival and burst time for  p2 : Enter the arrival and burst time for  p3 : Enter the arrival and burst time for  p4 : 
P	AT	BT	CT	TAT	WT	RT
P1	0	2	2	2	0	0
P2	1	2	2	1	-1	-1
P3	5	3	8	3	0	0
P4	6	4	9	3	-1	-1
https://ideone.com/nUU1jW
language:
C (gcc 8.3)
created:
4 days ago
visibility:
public

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