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  1. <?php $year=2036; if($year%400==0 || ($year%100!=0 && $year%4==0)) echo $year.' is Leap Year'; else echo $year.' is Not a Leap Year'; ?>
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2036 is Leap Year
https://ideone.com/pZKCEn
language:
PHP (php 7.3.5)
created:
13 days ago
visibility:
public

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