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  1. #include <stdio.h>
  2. #include <stdlib.h>
  3. #include <math.h>
  4.  
  5.  
  6. void nhap(int *n, int *m, float **a, float **b){
  7. 	scanf("%d %d", n, m);
  8. 	*a = (float*)malloc((*n + 1) * sizeof(float));// (*n + 1)  *(n + 1)
  9. 	*b = (float*)malloc((*m + 1) * sizeof(float));
  10.  
  11. 	printf("Nhap he so P(x);\n");
  12. 	for(int i = 0; i < *n + 1; i++)
  13. 	{
  14. 		printf("Nhap he so bac %d: ",i);
  15. 		scanf("%f",  (*a + i) );
  16. 	}
  17. 	printf("Nhap he so Q(x);\n");
  18. 	for(int i = 0; i < *m + 1; i++)
  19. 	{
  20. 		printf("Nhap he so bac %d: ",i);
  21. 		scanf("%f", (*b + i));
  22. 	}
  23. }
  24.  
  25. float ketQuaDaThuc(float *a, int bac, float x){
  26. 	float res = 0;
  27.  
  28. 	for(int i = 0; i <= bac; i++){
  29. 		res += a[i] * pow(x, i);
  30. 	}
  31.  
  32. 	return res;
  33. }
  34.  
  35. void tinhKetQua(float *d1, float*d2, float*a, float *b, int n, int m){
  36. 	float res = 0;
  37. 	printf("Nhap d1, d2: ");
  38. 	scanf("%f %f", d1, d2);
  39.  
  40. 	res += ketQuaDaThuc(a, n, *d1) + ketQuaDaThuc(b, m, *d2);
  41.  
  42. 	printf("Ket qua cua S = %.2f\n", sqrt(res) - 2013);
  43. }
  44. int max(int a, int b){
  45. 	if(a > b)
  46. 		return a;
  47. 	return b;
  48. }
  49. void heSoDaThucHieu(float*a, float *b, int n, int m){
  50. 	int k = max(m, n);
  51.  
  52. 	float *c = (float*)malloc((k + 1) * sizeof(float));
  53. 	for(int i = 0; i <= k; i++){
  54. 		if(i > n){
  55. 			c[i] = -b[i];
  56. 		}
  57. 		else if(i > m){
  58. 			c[i] = a[i];
  59. 		}
  60. 		else{
  61. 			c[i] = a[i] - b[i];
  62. 		}
  63. 	}
  64.  
  65. 	for(int i = 0; i <= k; i++){
  66. 		printf("He so bac %d cua P(x) - Q(x) la: %.2f\n", i,c[i]);
  67. 	}
  68. }
  69. int main (){
  70. 	int n, m;
  71. 	float *a, *b, d1, d2;
  72. 	nhap(&n, &m, &a, &b);
  73. 	tinhKetQua(&d1, &d2, a, b, n, m);
  74. 	heSoDaThucHieu(a, b, n, m);
  75. }
Success #stdin #stdout 0.01s 5312KB
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stdin
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Standard input is empty
stdout
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Nhap he so P(x);
Nhap he so bac 0: Nhap he so Q(x);
Nhap he so bac 0: Nhap d1, d2: Ket qua cua S = -2013.00
He so bac 0 cua P(x) - Q(x) la: 0.00
https://ideone.com/qIKOAE
language:
C++14 (gcc 8.3)
created:
3 days ago
visibility:
public

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